Formula for universal Gravitation

June 24, 2016


Fg = force due to gravity between the two objects (N)

G = the Gravitational Constant

m1 and m2 = the two masses (kg)

r = the distance between the two objects’ centres (m)

This formula shows that any objects with mass will pull towards each other with a gravitational force.

You might have heard the phrase in a Social Studies class. It usually refers to one country having a political or military influence over another.
  • We usually say that an object has a gravitational field around it.
  • Any field is just a sphere of influence around the object. The closer you get, the more you are affected by it.
  • In the case of gravity, the bigger the mass of the object, the bigger the field.
  • The formula also shows that the closer the objects are, the greater the effect of the gravitational field.
  • This is the first formula that you'll see from a family of formulas called the "inverse square formulas". They all look pretty much the same, and lead physicists to believe that there are many common connections and relationships throughout all of physics.

    Newton then turned his attention to trying to find the value for the Gravitational Constant, “G”.

  • Nope, it isn’t the acceleration due to gravity on Earth, 9.81m/s2.
  • Newton looked for a way of calculating the value for G from the formula above. If we solve that formula for G we get:
  • Let’s look at how we will substitute numbers into this formula.

  • Newton realized that the only thing he could measure a Fg for would be an object on Earth’s surface. An example would be you. We could calculate the force due to gravity on your body easily using Fg = mg.
  • We need to know the distance from the centre of the Earth to your centre… which we do have: 6.38e6 m. And yup, they even had a pretty good estimate of this in Newton's time!
  • We need to know your mass, which would be m1… that’s no problem.
  • The last thing we need, m2, is the mass of the Earth. Oh, oh. That one is a problem.
  • In Newton’s time no one had any idea how heavy the Earth really was.
  • If we knew G, then we could calculate the mass of the Earth, but that’s what we are trying to calculate here!
  • Newton continued to look for some way to calculate G indirectly, but never found a way.
  • Cavendish's Torsion Balance

  • He attached a really heavy pair of metal balls to the ends of a long metal rod, and then hung the rod from a wire.
  • He then brought another pair of really heavy metal balls near the balls on the rod.
  • Cavendish knew that because they had mass they should pull on each other, but very weakly.
  • To measure this weak pull, he carefully measured how much the wire was twisting (torque) whenever he brought the other masses near by.
  • This is why the device he used is called a torsion balance.
  • After a lot of very careful, very tedious tries, he found that G was 6.67e-11Nm2/kg2.

  • Cavendish realized that because he knew the value for G, he could now calculate the mass of the Earth. That’s why he titled the paper that he published “Weighing the Earth.”
  • Example 1: Using values that you now know, Determine the mass of the Earth.

    We know that the force exerted on my body by the Earth is Fg = mg, where little “m” is my mass.

    I also know that the force could be found using Newton's big Universal Gravitation Formula, where one mass is a little “m” (my mass), and the other mass is a big “Me” (the mass of the Earth).

    Fg = Fg

    Me= 5.99e24 kg

    Notice that we were able to combine a couple of formulas to get the new formula .

  • Me does not always have to be the mass of the Earth. It could be the mass of the moon, Mars, an asteroid, whatever!
  • It let’s you calculate the acceleration due to gravity on that object if you know the other values.
  • Example 2: The planet Mars has a mass of 6.42e23 kg and a radius (from its centre to the surface) of 3.38e6 m. How much would a 60 kg person weigh on Mars compared to their weight on Earth? Determine How heavy he would “feel” he weighed in kilograms on Mars.

    On Earth the person has a weight of…

    Fg = mg

    = (60kg) (9.81m/s2)

    Fg = 5.9e2 N

    Gravity on Mars can be found using the formula shown above. Note: On an exam you need to show how you got this formula.

    g = 3.75m/s2

    So that person’s weight on Mars will be…

    = (60kg) (3.75m/s2)

    Fg = 2.3e2 N

    Remember, mass never truly changes... it's a constant. This is just how much you would feel like, in measurements you can better understand.

    To figure out how much he would feel like he weighed on Mars in kilograms, remember that we spend our lives here on Earth and our body thinks that 9.81m/s2 is what gravity should always be. Therefore, this person will feel like his mass is…

    m = Fg / g

    = (2.3e2 N) / (9.81m/s2)

    m = 23 kg

    Example 3: Determine the force of attraction between a 15.0kg box and a 63.0 kg person if they are 3.45m apart.

    I have to assume that the distance I have been given is the distance between the two centres of the objects.

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